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Maryland baseball’s AJ Lee named Big Ten Player of the Week

This is Lee’s first conference honor this season.

Lila Bromberg / Testudo Times

After leading Maryland baseball to a sweep over Iowa this past weekend to secure the No. 6 seed in the Big Ten Tournament, shortstop AJ Lee earned some recognition from the conference.

Lee received Big Ten Player of the Week honors for the first time this season after a week where he hit .588 (10-for-17) with six RBIs, three home runs and eight runs scored.

Lee hit home runs in three consecutive games last week, including a walk-off two-run shot in the series opener to beat the Hawkeyes, 8-6. Combining his runs scored and batted in, Lee himself accounted for 14 of Maryland’s 32 runs scored last week.

Lee went into a slump recently after tearing it up for most of April, but his play over the weekend was big for the Terps, who climbed back over .500 and qualified for the Big Ten tournament for the first time since 2017.

As the No. 6 seed, Maryland will play No. 3-seeded Illinois on Wednesday at 10 a.m. ET. The Big Ten tournament is a double-elimination tournament, so if Maryland wins, it will play the winner of Michigan and Ohio State on Thursday at 6 p.m. ET. If the Terps lose, they will play the loser of Michigan-Ohio State on Thursday at 10 a.m. ET in an elimination game. All games will be broadcast on the Big Ten Network and the full bracket can be found below.